Y=16x^2+4.8x

Solution for Y=16x^2+4.8x equation:

=16Y^2+4.8Y

We move all terms to the left:

-(16Y^2+4.8Y)=0

We get rid of parentheses

-16Y^2-4.8Y=0

a = -16; b = -4.8; c = 0;
Δ = b2-4ac
Δ = -4.82-4·(-16)·0
Δ = 23.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.8)-\sqrt{23.04}}{2*-16}=\frac{4.8-\sqrt{23.04}}{-32}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.8)+\sqrt{23.04}}{2*-16}=\frac{4.8+\sqrt{23.04}}{-32}
$